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2y^2-27y+36=0
a = 2; b = -27; c = +36;
Δ = b2-4ac
Δ = -272-4·2·36
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{441}=21$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-21}{2*2}=\frac{6}{4} =1+1/2 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+21}{2*2}=\frac{48}{4} =12 $
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